Question

The factorial 4! is equal to

Answer 1

\[4!=4*3*2*1\]

Answer 2

24?

Answer 3

Yes!

Answer 4

good stuff

Answer 5

Or just use a calculator that has the factorial sign

Answer 6

i tried finding the factorial of LGBAAA!!! in my scientific calculator. said "syntax error"

Answer 7

\[\large n! = n \times (n-1) \times (n-2) \times (n-3) \times .............. 3 \times 2 \times 1\]

Put n= 4 here..

Answer 8

@waterineyes n! = 4 * 3 * 2 * 1 * 3 * 2 * 1 = 144 O:

Answer 9

lol should only be \[n! = n \times (n-1) \times (n-2) \times \cdots \times 1\]

Answer 10

its the same thing igba

Answer 11

Unrolling factorials.

Answer 12

nope... x 3 x 2 x 1 is different like @nphuongsun93 said

Answer 13

Really???

Well, I got:

\[4! = 4 \times (4-1) \times (4-2) \times (4-3) = 4 \times 3 \times 2 \times 1 = 24\]

Answer 14

where's x 3 x 2 x 1 there? lol

Answer 15

What waterineyes wrote is the same as what Igba wrote; but igba just wrote it in a shorter form.
From memory you can also wrote it as: \(n! = n(n-1)!\)

Answer 16

@waterineyes i'm just teasing you
we all know this

Answer 17

That in the decreasing sense I wrote there...

You are also right lgba.. if we put 1 in the last then this will reduce confusion..

Answer 18

but the dotdotdot does express something ;)

Answer 19

No @Mimi_x3 you can also right it as:

\[n! = n(n-1)(n-2)!\]

Ha ha ha..

Answer 20

No you are wrong lgba..
Careful..

Answer 21

?

Answer 22

\[n! = (n(n-n)!)!\]

Answer 23

Wel, from my notes \(n! = (n-1)!*n\)
Mynotes cannot be wrong.

Answer 24

@Mimi_x3 you can subtract 1 upto the length you want..

Answer 25

\[n! = (n \times 1)!\]

Answer 26

\[n! = (n \times 0!)!\]

Answer 27

\[ \huge \huge n! = n! \]

Answer 28

\[n! = 42!\]

Answer 29

\[\large n! = \sqrt{(n!)^2}\]