Question

solve the system
x+4y-z=3 (1)
x+5y-2z=5 (2)
3x+12y-3z=9 (3)

Answer 1

how did you start it?

Answer 2

substitution by elimination. x-4y+2z=3 (1), x+5y-2z=5 (2)

Answer 3

Multiply both the sides by (-1)..

Answer 4

so x=-1-3y?

Answer 5

\(x + 3y =-1\)

Answer 6

cool. thanks

Answer 7

Welcome dear..

Answer 8

?

Answer 9

um... nobody solved anything

Answer 10

What is the meaning??

Answer 11

lol

Answer 12

you are only give two equations?

Answer 13

...and 3 variables?

Answer 14

Question is not that..

Answer 15

and i dont know where -x - 3y = 1 came either...maybe that's the third

Answer 16

@jrzyby1 please type the original question in full

Answer 17

hether or not i need to multil
ply by -1 or not

Answer 18

I think he is just looking for how to write the given equation in standard form..
Coefficient of x is -1 so we can make it one..

Answer 19

correct

Answer 20

@jrzyby1 what is this:

substitution by elimination. x-4y+2z=3 (1), x+5y-2z=5 (2)

you typed this and said that is where you got what you asked us about from

Answer 21

but still where did -x - 3y = 1 came from

Answer 22

that too

Answer 23

and x + 3y = -1 isnt standard form either...too many questions o.O

Answer 24

He asked it directly and randomly you can say that..

Answer 25

yes. that was what I got and didn't know how to finish the equation
I wanted to find out if multiplying the last equation by (-10 would give my the variable

Answer 26

oops (-1)

Answer 27

give you the variable?

Answer 28

Now I am in doubt too..
Ha ha ha..

Answer 29

@jrzyby1 are you solving a system of equations?
x-4y+2z=3 (1), x+5y-2z=5 (2)

if not, why did you type this?

Answer 30

and I didn't hear anybody ask for standard form either

Answer 31

I was sustituting-2 into the first equation and added it to the second which gave me the result in question. I didn't know if I needed to multiply it by (-1) to finish it.

Answer 32

so in the original question, you are given only 2 equations with 3 variables
correct?

Answer 33

x-4y+2z=3 (1)
x+5y-2z=5 (2)

is this the \(original\) problem?

Answer 34

if you multiplied the first equation by 2..then where's the z variable?

Answer 35

oh my, the 3
equation ended in zeros. 3x+12y-3z=9

Answer 36

@jrzyby1 so the original problem is

x-4y+2z=3 (1)
x+5y-2z=5 (2)
3x+12y-3z=9 (3)

correct?

Answer 37

correct

Answer 38

now we are getting somewhere...

Answer 39

please type the problem in full next time, you have not done it correctly so far and have not provided enough info to solve it even if you had

Answer 40

I am going to modify your post for you so you can get a correct answer
the one you have above is wrong, I promise you
is that okay with you?

Answer 41

wait your 4 in the (1) is (+)

Answer 42

x+4y+2z=3 (1)
x+5y-2z=5 (2)
3x+12y-3z=9 (3)

correct (please double-check)

Answer 43

hang on. let me giv eyou it again

Answer 44

yes, please be 100% sure of the original problem

Answer 45

x+4y-z=3(1)
x+5y-2z=5(2)
3x+12y-3z+9(3)

Answer 46

okay, I think you should repost this problem in full...

Answer 47

so am I wrong so far?

Answer 48

well you still didn't type the problem right...
you must be more careful if we are to help you..
is not equation (3) supposed to have an = in it?

Answer 49

solve the system
x+4y-z=3 (1)
x+5y-2z=5 (2)
3x+12y-3z=9 (3)

is what I am guessing the original problem is

Answer 50

yes

Answer 51

I'm going to repost this problem for you, okay?
that way you will get the most help I think

Answer 52

k

Answer 53

sorry for the hassle

Answer 54

it's okay
check it out I posted your problem for you, it's at the top