I think this should be easy? I know I have to simplify like, on each side before solving but the exponent always throw me off D:

Question

anonymous · Answer

parthkohli · Answer

Y U NO FACTOR?

anonymous · Answer

-____-

mimi_x3 · Answer

$$\large \frac{x-y}{x^{2}-1}  *\frac{x-1}{x^{2}-y^{2}}   $$

parthkohli · Answer

$x^2 - y^2$ and $x^2 - 1$ are factor-able(difference of squares).

mimi_x3 · Answer

try and factor the RHS

anonymous · Answer

Okay on the first numerator and the second denominator can I just do 1 and 2?

parthkohli · Answer

When you factor, just cancel the diagonal terms.

anonymous · Answer

Lol I know how to factor, I just don't know what to do when exponents are involved.

mimi_x3 · Answer

Yeah $x-y$ and $x^2-y^2$ is alike

anonymous · Answer

easy question lol

anonymous · Answer

$$a^2 - b^2 = (a+b)(a-b)$$

anonymous · Answer

write denominator as (x-1)(x+1) and (x-y)(x+y)

parthkohli · Answer

That's what we are trying to tell you. Can you factor?

anonymous · Answer

Okay so now |dw:1342097440272:dw|

mimi_x3 · Answer

$x^2-y^2 = (x-y)(x+y)$

anonymous · Answer

use the formula  a^2 - b^2  = (a+b) (a-b)

anonymous · Answer

How come 2??

anonymous · Answer

^That is the part I get stuck on, Mimi. I'm like how the heck...

parthkohli · Answer

Why do we have that 2?

anonymous · Answer

Factorise denominator like:
$$x^2 - 1 = (x+1)(x-1)$$

anonymous · Answer

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