In the Bohr model of the hydrogen atom, an electron can orbit a proton (the nucleus) in a circular orbit of radius 8.46E-10 m. What is the electric potential at the electron's orbit due to the proton?

Question

anonymous · Answer

I got this one right: 1.70V
The next ones stump me:

What is the kinetic energy of the electron?

What is the total energy of the electron in its orbit?

What is the ionization energy that is, the energy required to remove the electron from the atom and make it to r = infinity at rest?

fwizbang · Answer

The electron is in a circular orbit, so its acceleration must be the centripetal acceleration.
Use Newton's 2nd law to relate this to the electric force

ujjwal · Answer

I am not sure if you are supposed to do it this way but if i were to solve it, i would solve it like this:

For hydrogen atom:
radius of $n^{th}$ orbit= 0.53$A^0$ $\times n^2$
So, the given data suggests it's 4th orbit oh hydrogen atom.
Now Total energy in nth orbit of hydrogen atom= -13.6/$n^2$ eV
So, total energy in 4th orbit=-0.85 eV
Now, Total Energy=-KE  (This is always the case, formulas will give you this result)
So, KE in 4th orbit=0.85eV

Now ionization energy= energy to be given so as to make the total energy of electron zero (energy of electron at infinite energy level is zero) 
So, it would be 0.85 eV in this case..

P.S. you can convert eV into joule.
1 eV= $1.6 \times 10^{-19}$ Joule