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Mathematics 28 Online
OpenStudy (anonymous):

k=1 sigma K tends to infinity (k+1)/(k+2) this series is converges or diverges../

OpenStudy (anonymous):

Um...put some numbers in for k...

OpenStudy (anonymous):

put the number then..? how can i identify this series is diverges or converges

OpenStudy (anonymous):

Inspection...(by eye). Try k=1, 10,100, 1000

OpenStudy (anonymous):

this series is telescopoing..?

OpenStudy (anonymous):

suppost i put 1 the result is 2/3 how can i identify the series 2/3 is diverges or converges..?

OpenStudy (anonymous):

2/3 is not a series....

OpenStudy (anonymous):

can u explain now plz for this series..?

OpenStudy (anonymous):

Your series is for values ok from 1 to infinity (although infinity is not actually a value). In other words what happens to your expression as k increases without limit? As u say, with k = 1, your expression is 2/3 but when k is 10 then it is 11/12 and when it is 100 then it is 101/102 and so on.... If I use decimals instead of fractions: 0.666666.... 0.9166666.... 0.999196...

OpenStudy (anonymous):

then

OpenStudy (anonymous):

?

OpenStudy (anonymous):

series is converges or diverges..? can u know..?

OpenStudy (anonymous):

Did you read my post?

OpenStudy (anonymous):

yes... but i cant undersstnd what u say..?

OpenStudy (anonymous):

Which part?

OpenStudy (anonymous):

how can i identify ...?

OpenStudy (anonymous):

As k increases, what happens to the value of the expression?

OpenStudy (anonymous):

value increses.

OpenStudy (anonymous):

bro we use the ratio test? for identify the series converges or diverges..?

OpenStudy (anonymous):

The value increases.... with or without a limit?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Yes, what?

OpenStudy (anonymous):

i cant what u say... i cant understand .. u r understnading style is very chep

OpenStudy (anonymous):

U said the value increases.... How big does it get?

OpenStudy (anonymous):

u ask me qus qus qus i told i cant understnd plz explain now but u again and again ask the qus.

OpenStudy (anonymous):

yup definitly i told u value is increse..

OpenStudy (anonymous):

k=1 -> 2/3 k = 10 ->11/12 k = 100 -> 101/102 k = 1000 -> 1001/1002 k = 10000 -> 10001/10002 Can u see?

OpenStudy (anonymous):

yes i see

OpenStudy (anonymous):

OK, what do you see?

OpenStudy (anonymous):

value is dicreases.?

OpenStudy (anonymous):

The value is getting closer and closer to 1

OpenStudy (anonymous):

yup so series is diverges.?

OpenStudy (anonymous):

Convergent means to come to a limit, divergent means there is no limit. Here the limit is 1.

OpenStudy (anonymous):

use the divergence test show that the series is diverges this is my real qus

OpenStudy (anonymous):

U mean convergence test, there is no need in this case, the answer is obvious.

OpenStudy (anonymous):

why dont need in this case../

OpenStudy (anonymous):

What is 1+1+1+1+1+..........?

OpenStudy (anonymous):

i dont kniw

OpenStudy (anonymous):

Infinite, right? As big as you want to keep adding more 1's. Basically, that is your question, you have an infinite number of terms that are nearly 1 so the sum of all those terms is infinite.

OpenStudy (anonymous):

oka

OpenStudy (anonymous):

So your sum diverges....

OpenStudy (anonymous):

1/1+6

OpenStudy (anonymous):

divergs or convetgs

OpenStudy (anonymous):

??

OpenStudy (anonymous):

same qus but value is chagen

OpenStudy (anonymous):

i also know this site..

OpenStudy (anonymous):

All the explanation and tests are mentioned there....

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