k=1 sigma K tends to infinity (k+1)/(k+2) this series is converges or diverges../
Um...put some numbers in for k...
put the number then..? how can i identify this series is diverges or converges
Inspection...(by eye). Try k=1, 10,100, 1000
this series is telescopoing..?
suppost i put 1 the result is 2/3 how can i identify the series 2/3 is diverges or converges..?
2/3 is not a series....
can u explain now plz for this series..?
Your series is for values ok from 1 to infinity (although infinity is not actually a value). In other words what happens to your expression as k increases without limit? As u say, with k = 1, your expression is 2/3 but when k is 10 then it is 11/12 and when it is 100 then it is 101/102 and so on.... If I use decimals instead of fractions: 0.666666.... 0.9166666.... 0.999196...
then
?
series is converges or diverges..? can u know..?
Did you read my post?
yes... but i cant undersstnd what u say..?
Which part?
how can i identify ...?
As k increases, what happens to the value of the expression?
value increses.
bro we use the ratio test? for identify the series converges or diverges..?
The value increases.... with or without a limit?
yes
Yes, what?
i cant what u say... i cant understand .. u r understnading style is very chep
U said the value increases.... How big does it get?
u ask me qus qus qus i told i cant understnd plz explain now but u again and again ask the qus.
yup definitly i told u value is increse..
k=1 -> 2/3 k = 10 ->11/12 k = 100 -> 101/102 k = 1000 -> 1001/1002 k = 10000 -> 10001/10002 Can u see?
yes i see
OK, what do you see?
value is dicreases.?
The value is getting closer and closer to 1
yup so series is diverges.?
Convergent means to come to a limit, divergent means there is no limit. Here the limit is 1.
use the divergence test show that the series is diverges this is my real qus
U mean convergence test, there is no need in this case, the answer is obvious.
why dont need in this case../
What is 1+1+1+1+1+..........?
i dont kniw
Infinite, right? As big as you want to keep adding more 1's. Basically, that is your question, you have an infinite number of terms that are nearly 1 so the sum of all those terms is infinite.
oka
So your sum diverges....
1/1+6
divergs or convetgs
??
same qus but value is chagen
i also know this site..
All the explanation and tests are mentioned there....
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