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\[5^{x - 3} . 3^{2x - 8} = 225 \]
I think this involves log, but I'm new to it so I would be very grateful if you explain.
yeah it does
log(a.b)=loga+logb
log a^x=xloga
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Yes .... but how does that relate hear?
sorry here.
x-3 and 3x-8?
ok i got it x=5
I'm still not sure how to proceed ...
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just notice that \[225=15^2=5^2 * 3^2\]
Yes.
then x-3=2x-8 and x=5
altough log would be ideal here but, on slight inspection, you should be easily able to see that: 225 = 5^2 . 3^2 using which you can compare LHS and RHS..
sorry didnt see @mukushla 's post ;
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