Question

The sum of 6 and twice a number is multiplied by three. This product is greater than or equal to 66. What is the smallest value possible for this number?

Answer 1

First solve the inequality for x.
The sum of 6 and twice a number (the unknown, represented by the variable x) multiplied by 3 translates to this expression algebraically: 3(2x + 6).
This product is greater than or equal to 66.
Expand the multiplication to: 6x + 18, which is greater than or equal to 66.
Then subtract 18 from both sides to get: 6x is greater than or equal to 48.
Then divide both sides by 6 to get: x is greater than or equal to 8.
If x is greater than or equal to 8, then x could be 8 or 9 or 10, etc., any number from 8 on up into infinity! The smallest possible value for x given these constraints is 8.

http://wiki.answers.com/Q/The_sum_of_6_and_twice_a_number_is_multiplied_by_three_This_product_is_greater_than_or_equal_to_66_What_is_the_smallest_value_possible_for_this_number#ixzz20Q7BNJbG

Answer 2

let number = x
twice the number = 2x
sum of six and twice the number is 2x+6
now multiply by 3
3(2x+6)
\[3(2x+6) \ge 66\]

Answer 3

now apply simple math rules to get the answer. good luck