Question

Factor completely 2c5 + 44c4 + 242c3

Answer 1

@Caramel_823 We have
\[2c^5+44c^4+242c^3\]
Can you take \(c^3\)out from each of the terms?

Answer 2

Ok so now its \[2c ^{2} + 44c + 242c\] right ?

Answer 3

oh you forget the c with 242, there won't be any

Answer 4

Ok so everything else is right ?

Answer 5

Well these are my answer choices :
A.2c3(c + 11)2
B. 2(c + 11)2
C. 2c3(c + 11)(c – 11)
D. 2c3(c2 + 22c + 121

Answer 6

We'll get there
\[c^3(2c^2+44c+242)\]
Now take 2 common from the terms inside the bracket!!

Answer 7

Ok \[c ^{3}(c ^{2}+11c+121)\]

Answer 8

the 2 will be outside the bracket.

Answer 9

So the answer will be C ?

Answer 10

nope, we still have one more step
\[2c^3(c^2+11c+121)\]
Do you know the expansion of \((a+b)^2\)?

Answer 11

@jim_thompson5910 help for a best response?

Answer 12

Correct answer is > 2c3(c + 11)2