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Mathematics 20 Online
OpenStudy (anonymous):

log^32=x+2

OpenStudy (anonymous):

Are you sure log is not in the right hand side??

OpenStudy (turingtest):

if you mean log base 3 please write log_3(2)=x+2

OpenStudy (turingtest):

less confusing that way

OpenStudy (anonymous):

I'm very sorry I forgot the 4! it is log_4(32)=x+2 I;m so sorry for the confusion.

OpenStudy (turingtest):

ah, much better :)

Parth (parthkohli):

\( \color{Black}{\Rightarrow \log_a b = c \Longrightarrow a^c = b}\)

Parth (parthkohli):

\(a = 4, b = 32, c = x + 2\)

Parth (parthkohli):

Must seem much easier now, eh?

OpenStudy (anonymous):

so 4^(x+2)=32

Parth (parthkohli):

\( \color{Black}{\Rightarrow 4^{x + 2} = 32}\) \( \color{Black}{\Rightarrow \Large (2^2)^{x + 2} = 32}\)

Parth (parthkohli):

\( \color{Black}{\Rightarrow \large2^{2x + 4} = 32}\) \( \color{Black}{\Rightarrow 2^{2x + 4 } = 2^5 \Longrightarrow 2x + 4 = 5 }\)

Parth (parthkohli):

Does that make it better for you, @Bunnijjane ?

OpenStudy (anonymous):

\[\large Log_42^5 = x+2 \implies 5.Log_{2^2}2 = x + 2 \implies \frac{5}{2} = x + 2\] \[2x + 4 = 5\] \(2x = 1\)

Parth (parthkohli):

@waterineyes \log can be used instead of plainly typing out 'Log' :P

OpenStudy (anonymous):

very much so @ParthKohli so sub 4 2x=1 so x=1/2?

OpenStudy (anonymous):

It is my way..

OpenStudy (anonymous):

Yes you are right...

OpenStudy (anonymous):

Thank you!

OpenStudy (anonymous):

Welcome dear..

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