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OpenStudy (anonymous):
log^32=x+2
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OpenStudy (anonymous):
Are you sure log is not in the right hand side??
OpenStudy (turingtest):
if you mean log base 3 please write
log_3(2)=x+2
OpenStudy (turingtest):
less confusing that way
OpenStudy (anonymous):
I'm very sorry I forgot the 4! it is
log_4(32)=x+2
I;m so sorry for the confusion.
OpenStudy (turingtest):
ah, much better :)
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Parth (parthkohli):
\( \color{Black}{\Rightarrow \log_a b = c \Longrightarrow a^c = b}\)
Parth (parthkohli):
\(a = 4, b = 32, c = x + 2\)
Parth (parthkohli):
Must seem much easier now, eh?
OpenStudy (anonymous):
so 4^(x+2)=32
Parth (parthkohli):
\( \color{Black}{\Rightarrow 4^{x + 2} = 32}\)
\( \color{Black}{\Rightarrow \Large (2^2)^{x + 2} = 32}\)
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Parth (parthkohli):
\( \color{Black}{\Rightarrow \large2^{2x + 4} = 32}\)
\( \color{Black}{\Rightarrow 2^{2x + 4 } = 2^5 \Longrightarrow 2x + 4 = 5 }\)
Parth (parthkohli):
Does that make it better for you, @Bunnijjane ?
OpenStudy (anonymous):
\[\large Log_42^5 = x+2 \implies 5.Log_{2^2}2 = x + 2 \implies \frac{5}{2} = x + 2\]
\[2x + 4 = 5\]
\(2x = 1\)
Parth (parthkohli):
@waterineyes \log can be used instead of plainly typing out 'Log' :P
OpenStudy (anonymous):
very much so @ParthKohli so sub 4
2x=1
so x=1/2?
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OpenStudy (anonymous):
It is my way..
OpenStudy (anonymous):
Yes you are right...
OpenStudy (anonymous):
Thank you!
OpenStudy (anonymous):
Welcome dear..
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