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Mathematics 21 Online
OpenStudy (anonymous):

The red graph (1) is the graph of f(x) = 2x. Describe the transformation of the blue function (2) and write the equation of the graph.

OpenStudy (anonymous):

OpenStudy (anonymous):

@nphuongsun93

OpenStudy (anonymous):

you understand it @Romero orrr..?

OpenStudy (anonymous):

To clarify, that is \(f(x)=2^x\).

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Looks like it was shifted to the right 5 and up 2, right?

OpenStudy (anonymous):

i believe so?

OpenStudy (anonymous):

Okay, so if we're shifting a graph up 2, how would you change the equation to represent that? Think about it this way: we're making it so that for every value of x, the value of y is 2 more than it was in the old equation.

OpenStudy (anonymous):

add +2 i guess?

OpenStudy (anonymous):

Right, so how would you write that equation? The whole equation, I mean.

OpenStudy (anonymous):

fx=2x+2?

OpenStudy (anonymous):

Right. Just to be clear, it's better to write it as 2^x, so that we know it's \(2^x\) rather than just \(2x\). Anyways, next step, you want to shift it to the right five. So what that means is for each x, we want the value of y to be what it used to be five to the left. Does that make sense why that is?

OpenStudy (anonymous):

so is that the final equation?

OpenStudy (anonymous):

We still have to shift it five to the right, remember?

OpenStudy (anonymous):

so +5?

OpenStudy (anonymous):

That would shift it five up, not five to the right :P

OpenStudy (anonymous):

k..

OpenStudy (anonymous):

To shift an equation to the right or left, it's a bit more complicated. We basically want to change which value of x we're looking at, so we have to change it in the actual exponent. The part that's counterintuitive is that to shift to the left we add, and to shift to the right we subtract. So, for example, if we wanted to shift \(f(x)=2^x\) to the right one, we would do \(f(x)=2^{x-1}\).

OpenStudy (anonymous):

ok...is that the final equation

OpenStudy (anonymous):

f(x)=2^x+5

OpenStudy (anonymous):

whats the transformation of the blue function?

OpenStudy (anonymous):

Remember to use parentheses to make clear what you're saying. For example, if you want to say \(f(x)=2^{x+5}\), say 2^(x+5), but if you want to say \(f(x)=2^x+5\) then just say 2^x+5. So, the way you said that, I would interpret as \(f(x)=2^x+5\), which is the original graph shifted up 5. Remember, we want to shift it up 2, and to the right 5.

OpenStudy (anonymous):

can you show me

OpenStudy (anonymous):

Okay, here's another example. If we wanted to shift it down 3 and to the left 4, we would do this: \(f(x)=2^{x+4}-3\). The +4 in the exponent shifts it to the left 4, and the -3 shifts it down 3.

OpenStudy (anonymous):

f(x)=2^x+5+2

OpenStudy (anonymous):

First, remember to use parentheses so that it is clear what you mean. Second, remember that when shifting left and right, you add to shift left, and subtract to shift right.

OpenStudy (anonymous):

ok..how does that look?!

OpenStudy (anonymous):

How does what look? For an example of using parentheses, the example that I just gave where I shifted it down 3 and to the left 4 could be written as f(x)=2^(x+4)-3.

OpenStudy (anonymous):

the final equation. How does the final equation look??

OpenStudy (anonymous):

Why do you need to ask me? You have all the tools you need to put it together. I've told you how it works, and given you multiple examples. What do you think the final equation is?

OpenStudy (anonymous):

I. DONT.KNOW.

OpenStudy (anonymous):

You don't need to know, you just need to think. Try to figure it out. Actually work on it. I'll tell you if what you come up with is correct or not.

OpenStudy (anonymous):

f(x)=2^(x+5)+2

OpenStudy (anonymous):

That's very close. That actually shifts it to the left instead of to the right, though. When shifting left and right, you use + to shift left, and - to shift right.

OpenStudy (anonymous):

soooooooooo -2?

OpenStudy (anonymous):

?

OpenStudy (anonymous):

whats the transformation of the blue function?

OpenStudy (anonymous):

The +2 is to shift it up. The part that is wrong is the left/right shift, that's the one that needs to be - instead of +.

OpenStudy (anonymous):

x-5+2?

OpenStudy (anonymous):

Write the whole thing properly so I know what you mean

OpenStudy (anonymous):

f(x)=2^(x-5)+2

OpenStudy (anonymous):

???????????????

OpenStudy (anonymous):

can anyone help me? ive been stuck on this problem for 3 hours..literally. I really just need the answer

OpenStudy (anonymous):

Yeah, the last thing that you posted was correct.

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