the x-intercepts of a quadratic function are -3 and 5. What is the equation of its axis of symmetry??
Remember that when your looking at a quadratic equation, you are looking at a parabola. What is the axis of symmetry in a parabola?
the axis of symmetry is the vertical line that divides the parabola
Exactly. So what will your formula then look like and where will it be located?
well the formula is x=-b/2a...and its an x coordinate
Pardon me, I mean what is the formula for the line that splits a parabola.
The important part here is to understand that the equation for the parabola does not matter, but the symmetry of the parabola proves that it will always hit the x axis at exactly 2 points, of which both are an even number of units away from the axis of symmetry.
Does that help?
sorta...
Alright. Imagine we have a parabola. We move the entirety of the lines to the right, that means the whole parabola moves to the right. The axis of symmetry, which splits it down the middle, should also move correct?
the question im trying to answer is multiple choice... a. x=-3 b. x=1 c. x=5 d. x=-15
yes correct
So then the axis of symmetry should always be exactly in between the points where it touches the axis correct?
x-axis.
yes
i just don't know how to find that lol
Find the middle point between your two x points, and you will have the x point at y = 0. But we know the symmetry equation should be x = ?. And knowing that x =? is a straight line up and down we should be able to use the point that we found before.
A good way to find the middle point is always to add up the two points, and divide by 2. So (5+(-3))/2.
Is this helping you to understand?
ya for sure!....based on what you told me i got my final answer to be x=1..is that correct?
That is correct. Because the graph is shifted, and we know where it touches x, we don't need to use the formula but rather know that is symmetrical at the line between the x points where it touches. Good job following me I know it can be hard keep it up!
lol well i appreciate any help i can get! thank you sooo much this makes so much more sense now:)
would you mind helping me with one more question?
What is the quation?
well i just want to know how you would find the x intercepts if you were given the solutions to a quadratic equation...so basically the reverse
Like? If it gave you the solutions.. for example.. (x-5)(x+2) which is the parabola x^2-3x-10. You set x-5=0 and x-2=0 and solve for x and those are your two points.
Or you could use the multiply out your solutions and use your formula using the b component.
well the question is ....the solutions to a quadratic equation are x=2 or x=3. what are the x intercepts of the related quadratic function
What is the relation between the functions?
Do you want to find the quadratic they are from or a related one?
related
at least thats what the question says haha
Are the questions in order?
in order?
im sorry english is not my first language
I think I understand the question now. It should relate to the problem we solved before correct? Where the points of the quadratic were x = -3 and x = 5.
What are the answers?
no....its ment to be different....the exact question that im looking at is the solutions to a quadratic equation are x=2 or x=-3. What are the x-intercepts of the related function a. 2 and -3 b. -1 only c. -2 and 3 d. -6 and 6
Ok so this is relative to the other solutions. First you should solve for the quadratic, then you should look and see how you can manipulate the equation to come up with a pair of x coordinates that fits.
Does that make sense?
yes
thank you for your help!
For example, could the x components only be -1?
Anytime. good luck!
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