Question

*PRECALCULUS***
Solve each equation for x.... (I will post the questions in a reply)

Answer 1

Looks doable... are you still there?

Answer 2

now i am :)

Answer 3

Ok, let's do the first one...
Remember this:
\[y = \log _{b}x\]
then
\[b^{y} = x\]

Answer 4

ok

Answer 5

so the first one would be 3^5=x^2+18?

Answer 6

That's right. Can you do it from there? :)

Answer 7

243=x^2+18
so when I take the square root of x^2, do I also have to take the square root of the 18?

Answer 8

No, better to subtract 18 from both sides of the equality first :)

Answer 9

oh that's right! haha my teacher said that when i get to precalc, i'll start forgetting basic math :) Ok I can do it from there.

Answer 10

That's good. Have fun :D

Answer 11

I got x=15

Answer 12

Ok I can do the 2nd one on my own, but I'll need help on the 3rd one

Answer 13

All right, laws of exponents, when you multiply two exponentials with the same base, you add the exponents, aye? :)

Answer 14

Yes I believee so

Answer 15

so e^(2x+1)=1

Answer 16

that's right :)
Now, we're to solve it through logarithms, right?
Take the ln of both sides :)

Answer 17

lne^2x+1=ln1
2x+1=0
2x=-1
x=-1/2
:D

Answer 18

Nicely done. :)

Answer 19

Thank you sooooo much!!

Answer 20

No problem.