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Mathematics 19 Online
OpenStudy (anonymous):

3/x+3/x+1+3/x+2

OpenStudy (anonymous):

What's the question? Simplify?

OpenStudy (anonymous):

yes how do i get LCD?

OpenStudy (anonymous):

Well, if you turn the whole numbers into fractions by putting 1 under them, you've got a denominator of x on some and a denominator of 1 on the others...what's the LCM of x and 1?

OpenStudy (anonymous):

....... but there are 3 fractions.....^^^ 3/x+3.....+........3/x+1........+..........3/x+2

OpenStudy (anonymous):

im sorry the 1st fraction is 3/x

OpenStudy (anonymous):

3/x.....+........3/x+1........+..........3/x+2

OpenStudy (anonymous):

Ohhh. That's different. If you use parentheses, it becomes much clearer.

OpenStudy (anonymous):

sorry :P

OpenStudy (phi):

in this case, the common denominator is all three multiplied together It is x(x+1)(x+2)

OpenStudy (anonymous):

The easiest way to get a common denominator is just to multiply all the denominators...I'm not sure there's a quicker way in this case than doing that.

OpenStudy (anonymous):

x^3 +3x^2+2x ?

OpenStudy (phi):

I would not bother multiplying out the denominator. Leave it factored. but now multiply each fraction so its denominator is the common denominator for example, for the first fraction 1/x multiply by (x+1)(x+2)/(x+1)(x+2)

OpenStudy (phi):

*3/x not 1/x

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