Someone please explain to me how to work the problem in the attachment ?
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OpenStudy (anonymous):
there is no attachment, linda :)
OpenStudy (anonymous):
OpenStudy (anonymous):
so what's your problem?
OpenStudy (anonymous):
sorry, didn't read the topic carefully ...
OpenStudy (anonymous):
First hint: you can draq a circle with the center A that intersects C,D,E
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OpenStudy (anonymous):
*draw
OpenStudy (anonymous):
and then do i just add them ?
OpenStudy (anonymous):
add what?
OpenStudy (anonymous):
fe and ag
OpenStudy (anonymous):
i think thats correct
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OpenStudy (anonymous):
it only might be that the image has a bad solution, which seems to be the case because there is no 20
OpenStudy (anonymous):
so i was wrong with my circle
OpenStudy (anonymous):
yes, that is what i was confused about because my answer was 20 . .
OpenStudy (anonymous):
but we can use trigonometry to get af
OpenStudy (anonymous):
so we would have AF
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OpenStudy (anonymous):
do you know how to do trigonometry?
OpenStudy (anonymous):
i meant AE, sorry for that
OpenStudy (anonymous):
no not really . . .
OpenStudy (anonymous):
Final try:
You can use pythagorean theorem to get AF
Then add AF and FE
AE is the same like AC
OpenStudy (anonymous):
sorry i mixed the known parameters up
Do you now know how to do that?? And espacially do you know why to do it so??
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OpenStudy (anonymous):
okay so we get a soltion that is on the list! :DD
OpenStudy (anonymous):
yes i know how to do pythagorean theorem, but no i dont know why . .
OpenStudy (anonymous):
alright do you see that the triangle AGF has a an angle of 90° ?
OpenStudy (anonymous):
due to the bad resolution of the picture it's not really easiy
OpenStudy (anonymous):
19
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OpenStudy (anonymous):
cool man that you're just posting the solution. Great job, man
OpenStudy (anonymous):
._.
OpenStudy (anonymous):
angle AFG= 90
so AF=4
beacuse AC=AE
so AC=AE=AF+FE=19
OpenStudy (anonymous):
okay thanks for the answer but i cearly said that i neede someone to EXPLAIN it to me ! not give me the answer ! i was working it out ! i wont learn anythin if you just give the answer !
OpenStudy (anonymous):
so we gonna continue?ß
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OpenStudy (anonymous):
please ? !
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
you either can see that there is an angle 0f 90° at the angle AFG or you can know that because of the definition of tangent.
OpenStudy (anonymous):
which are in this case clearly secants
OpenStudy (anonymous):
`okay ! i never understood what a secant was . . .
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OpenStudy (anonymous):
A definition of a secant says that it meets the circle only in one point.
The radius between this point and the middle of the circle (this case FG) is also in an angle of 90° to the secant.
OpenStudy (anonymous):
oh okay gottcha !
OpenStudy (anonymous):
So you know that there must be an angle of 90° at AFG...
OpenStudy (anonymous):
Great
OpenStudy (anonymous):
yes okay now i im not so confused anymore with that
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OpenStudy (anonymous):
more explanation??
OpenStudy (anonymous):
yes, please , how do i find the length of AC ?
OpenStudy (anonymous):
okay, do you see that there is a line through A, G, D ?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
line through AGD is a mirror axis
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OpenStudy (anonymous):
do you get that?
OpenStudy (anonymous):
yes got it !
OpenStudy (anonymous):
And in normal symmetry all length keep the same
OpenStudy (anonymous):
perfect
OpenStudy (anonymous):
okat i understand that
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