Factor the Following Polynomials:
x²-81
x²-13x+36
Which polynomial is a special product and why?

Question

Factor the Following Polynomials:
x²-81
x²-13x+36
Which polynomial is a special product and why?

anonymous · Answer

need someone to walk me through step by step

anonymous · Answer

x^2-81=0
x^2=81
x=9

anonymous · Answer

okay
 so thats not the special product right?

anonymous · Answer

what do u mean by special product?

anonymous · Answer

Which polynomial is a special product and why?

anonymous · Answer

it says it in the question idk what it means

anonymous · Answer

lets do the second one, how did you start

anonymous · Answer

then mine is special

anonymous · Answer

i mean first one equation.

anonymous · Answer

$$x ^{2 } + 9^{2} $$ can you do it now?

anonymous · Answer

x=9 is not the answer

anonymous · Answer

okay so I'm at x^2+9^2 now what do i do

anonymous · Answer

Oops.. it x^2-9^2 not +

anonymous · Answer

ok i am doing

anonymous · Answer

x^2-9^2=(x+9)(x-9)

anonymous · Answer

okay now what

anonymous · Answer

(x-9) and (x+9) are the factors. You've got tha answers..:D well done

anonymous · Answer

Can we move on to the second?

anonymous · Answer

$$x^2-13x+36=0$$
now factorize
$$x^2-9x-4x+36=0$$
x and 4 common
$$x(x-9)-4(x-9)=0$$
bracket common
$$(x-9)(x-4=0$$
now 
x-9=0 or x-4=0
x=9 or x=4

anonymous · Answer

ok lets do the second

anonymous · Answer

2nd and 1st i have done with an easy way.

anonymous · Answer

x²-13x+36 is the question right? we don't have any common factor in the equation right now. Let's try to build.

anonymous · Answer

x²-13x+36 There is a std procedure to do such problems. Express the middle terms ( 13 ) as a sum of two no.s and last term ( 36 ) as a product. can you come up with any two no.s?

anonymous · Answer

@muhammad9t5 : You can't equate it to zero. No where it's given. Factorization and equation are two different things.

anonymous · Answer

ok