Question

how would I find the midpoint formula to this triangle?

Answer 1

you're looking for the midpoint of the sides?

Answer 2

Use the midpoint formula to find and plot the midpoint of each segment.

Answer 3

"midpoint of each segment" ... i'm guessing that means the midpoint of the sides of the triangle???

if yes, you'll need the coordinates of the vertices A, B, and C.... do you have them?

Answer 4

yeah, and no i don't have them

Answer 5

is the coordinate axes supposed to be in that picture?

Answer 6

because we need the coordinates of each vertex

Answer 7

yeah, its suppose to be, I just had to screen print it or else you wouldn't have been able to see it. how can i find those?

Answer 8

can you post the picture with the coordinate axes?

Answer 9

does this help?

Answer 10

well, once locate the coordinates of each vertex, use the midpoint formula. that will give you the midpoints of each side:

\[\huge (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}) \]

Answer 11

ok, here are the coordinates:
A(2, 2)
B(18, -2)
C(2, -6)

use the midpoint formula i wrote to find the midpoint of each side...

Answer 12

can you find the midpoint of AB? do you need help?

Answer 13

Please! I don't really understand it

Answer 14

\(\huge A(\color{red}2,\color{blue}2) \) \(\huge B(\color{red}{18},\color{blue}{-2}) \)

midpoint is \[\huge (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\rightarrow (\frac{2+18}{2}, \frac{18+(-2)}{2}) \]

can you finish from here?

Answer 15

sorry, should be:
midpoint is \[\huge (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\rightarrow (\frac{2+18}{2},\frac{2+(-2)}{2}) \]

Answer 16

so like 20/2, 0/2?

Answer 17

yes... simplify that...

Answer 18

10/1, 0/2

Answer 19

(10, 0) is more simplified...
so (10, 0) is the midpoint of side AB....

can you do that with the other sides? just do the same calculations with different coordinates....

Answer 20

0/2, 8/1 ?

Answer 21

for which one?

Answer 22

BC

Answer 23

for BC you should have something else...

Answer 24

B(18, -2)
C(2, -6)

\(\large (\frac{18+2}{2}, \frac{(-2)+(-6)}{2}) \)

simplify that...

Answer 25

Oh... I put the numbers in the wrong spot.20/2, -8/2

Answer 26

ok... that's correct but you need to simplify that... and don't forget these are coordinates so put them in between parentheses....

Answer 27

(10,1) and (-4,1)

Answer 28

no......

Answer 29

20\2 = 10\1 = 10
-8\2 = -4\1 = -4

so the midpoint of BC is (10, -4)

Answer 30

and then AC is (2,-4) ?

Answer 31

your x coordinate is correct... check the y coordinate...

Answer 32

(2,-2)

Answer 33

yes...:)

Answer 34

Thank you!! (:

Answer 35

yw...:)

Answer 36

Also, @dpaInc would this triangle be scalene, isosceles or equilateral?