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compute the derivative y=(e/e^x)^3
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\[y=(x/e^x)^3\]
\[ y' = 2 \frac x {e^x} \frac d {dx}\left( x e^{-x} \right) \]
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kind of lost
y= u^2 y'= 2 u u' Chain rule
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\[u= x e^{-x} \]
\[ u'= e^{-x} - x e^{-x}\\ 2 u u'= 2 x e^{-x} \left( e^{-x} - x e^{-x} \right)= 2 x e^{-2x} - 2 x^2 e^{-2x} \]
That is it.
is both chain rule and quotant rule
you can use product rule by writing \[ (x e^{-x})^2 \]
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ok eliassaab I had the first part right.Ok Andersfon12
@hooverst did you get it?
I have the final answer above.
yes Sir I got it !!
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yes SIr
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