Question

if the velocity is sqrt 180 - 16x find acceleration?

Answer 1

acceleration is the derivative of velocity

Answer 2

so what's \[\frac{d}{dx} (\sqrt{180 - 16x})\]

Answer 3

that confuses

Answer 4

hmmm..really?

Answer 5

which part?

Answer 6

let me try

Answer 7

sure

Answer 8

not getting

Answer 9

hmm you know the chain rule right?

Answer 10

make sure you have the right equation. is this it?
\[ \sqrt{ 180} - 16x\]

Answer 11

\[\Large \frac{d}{dx} (\sqrt {f(x)}) \implies \frac{d}{dx} [f(x)]^{1/2} \implies \frac 12 [f(x)]^{-1/2}] \times f'(x)\]

Answer 12

that's the chain rule for square roots

Answer 13

\[ \sqrt{180 - 16x}=(180-16x)^{\frac{1}{2}}\]

Answer 14

Just take the derivative of the right hand side

Answer 15

that's power rule + chain rule

Answer 16

can you just show them the derivative and let them simplify accordingly?

Answer 17

lol @yahoo! is gone =))

Answer 18

i am back ..... sorry my internet was in a problem

Answer 19

what is x here ?

Answer 20

so do you have an idea how to answer this now?

Answer 21

chains rule

Answer 22

yes

Answer 23

a= dv/dx . ax/dt

Answer 24

this is a chain rule

Answer 25

yep

Answer 26

a= dv/dx . dx/dt

Answer 27

dx/dt = v

Answer 28

Plzz help