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Mathematics 20 Online
OpenStudy (anonymous):

6.Using complete sentences, explain how to find the zeros of the function f(x) = 2x^3 – 9x + 3. (2 points)

OpenStudy (amistre64):

trial and error ...

OpenStudy (amistre64):

if there is a certain section of math that you are doing, then it prolly wants you to be more exacting. but without knowing what you are working with, trial and error is actually a valid method

OpenStudy (anonymous):

im doing graphing polynomial functions

OpenStudy (amistre64):

hmmm, is that spose to be a ^3 up there? or a ^2

OpenStudy (anonymous):

3

OpenStudy (amistre64):

without knowing some calculus, anything over ^2 is a bit challenging

OpenStudy (anonymous):

its algerbra 2

OpenStudy (amistre64):

2x^3 – 9x + 3 = 0 2x^3 – 9x = -3 x(2x^2 – 9) = -3 x (sqrt(2)x-3) (sqrt(2)x+3) = -3 factoring is usually helpful, but there is an art to it

OpenStudy (amistre64):

try x=0; f(0) = 3 try x=1; f(1) = -4 so it has to cross someplace between 0 and 1 at elast

OpenStudy (amistre64):

since 2x^3 is a positive odd function this thing will at least behave like x^3 |dw:1342281960889:dw| itll have at least 1 0, and at most 3 |dw:1342282006985:dw| and from this vantage point we shold know itll look something like this

OpenStudy (anonymous):

ok

OpenStudy (amistre64):

we can try a larger value to see what gets us back above the line; f(5) = 2(125) – 45 + 3 is greater than 0 f(3) = 2(27) – 27 + 3 is greater than 0 f(2) = f(5) = 2(8) – 18 + 3 = 1 is greater than 0 so there is another zero between 1 and 2 |dw:1342282246665:dw|

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