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Derivative of \[(3x^{2x+1})^{(x+1)}\]
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Sorry, y = \[(3x^{2x+1})^{(x+1)}\]
lol wow..
hmm i guess ln first
first multiply the exponents.
ln y = (x+1) ln (3x^(2x+1))
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do implicit differentiation
this is pretty simple if you are good with chain rule already...if not it can get confusing
(x+1)(2x+1)(3x^2x+1)^x (3x^2x)
Sorry, I typed the question wrong...I will re-post it
solve it further..... I also want to know
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