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calculus help.....find the area that the curve encloses: r=2 cos 3theta
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S=pi*r^2 you need to simplfy it
it's not A = indefinite integral of the bounds by the theta angles (1/2)r^2?
*definite
integrate : \[A=2\int\limits_{0}^{\pi}2 \cos 3 \theta d \theta \]
no that still doesn't give me the correct answer but thank you for yoru sugestions! the correct answer is pi
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but i just want to know how to get it
It's integral half r^2 dtheta but i am not too sure about the bounds, sorry.
2 int cos^2(3theta) dtheta between 0 and pi seems right.....
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