The parent function of the following graph is f(x)=(1/2)^x. what is the equation of the following graph?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
hero (hero):
Hint: wolframalpha
OpenStudy (anonymous):
yea..i dont know how to use it
hero (hero):
You should learn. It's not that difficult
OpenStudy (anonymous):
ya..i tried to use it before. dont know how.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
do you know the answer to this?
hero (hero):
I'm sorry to hear that. It works similar to how a calculator works.
hero (hero):
Yes
OpenStudy (anonymous):
do you know the equation?
hero (hero):
Yes
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
can you share it with me?
hero (hero):
I'm not sure if doing that will help you learn.
OpenStudy (anonymous):
one hint? notice that when \(x=0\) you get \(y=f(x)=2\)
OpenStudy (anonymous):
i think it will because youve done it before..
hero (hero):
Sorry
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
can you help tho
OpenStudy (anonymous):
let me look at your picture again. it is not that hard
OpenStudy (anonymous):
\[f(x)=(\frac{1}{2})^x\] is your "parent function" whatever that means now \(f(0)=(\frac{1}{2})^0=1\), but you do not have \((0,1)\) on the graph, you have \((0,2)\)
OpenStudy (anonymous):
so all you need to do is take \(f(x)=(\frac{1}{2})^x\) and multiply it by 2
OpenStudy (anonymous):
you can write \(2(\frac{1}{2})^x\) if you like
or even \((\frac{1}{2})^{x-1}\)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so after i multy 2 by 1/2 ill get the equation?
OpenStudy (anonymous):
careful here
OpenStudy (anonymous):
it is one half being raised to the power of \(x\) not \(2\times \frac{1}{2}\)
OpenStudy (anonymous):
so it is
\[g(x)=2\times (\frac{1}{2})^x\]
OpenStudy (anonymous):
so thats the equation?
Still Need Help?
Join the QuestionCove community and study together with friends!