Question

A spinner with three congruent sections is spun with the results as shown. What is P(1)? 1 3 3 2 1 2 1 1 3 3 2 1 1 1 2 2 2 3 3 1 3

Answer 1

The number of times that a spin comes up 1 divided by the total number of spins.

P(1) = 8/21

Answer 2

can you help me with one more question please


Two urns each contain green balls and blue balls. Urn I contains 4 green balls and 6 blue balls, and Urn II contains 6 green balls and 2 blue balls. A ball is drawn at random from each urn. What is the probability that both balls are blue?

Answer 3

its rather 2/51 3/20 or 4/153

Answer 4

and i got 3/20

Answer 5

Pr(blue in urn 1) = 6/(6+4) = 6/10 = 3/5
Pr(blue in urn 2) = 2(6+2) = 2/8 = 1/4

Multiply these two probabilities together, as you want them to occur together, 3/5*1/4 = 3/20 so yes you're right

Answer 6

you can think of it as two tables with different colored squares.
10 balls total in urn 1.
P1(blue)= 6/10
8 balls total in urn 2.
P2(blue)=2/8
Multiply together
6/10 * 2/8=0.15