Question

If A is the set of natural no. upto 100,then write all the subsets of A whose elements are even no.

Answer 1

Is it:

\[2^{50}\]

Not sure...

Answer 2

Not sure what you're asking here. The set of all subsets of A whose elements are even numbers would be \(2^B\) where \(B=\{2,4,...,100\}\)

Answer 3

let E be {2,4,...,100}. The set of all possible subsets of E is called power set of E:
\[E ^{P}\]

Answer 4

SUM[ 50!/(50-k)! ]

k : 1-> 50


is it same as 2^50 is it ?

im not sure not good with combinations and factorials

Answer 5

50 + 50*49 + 50*49*48 + 50*49*48*47 + .... 50!

Answer 6

shubham can you clarify the question? If you're looking for the number of subsets, it's \(2^{50}\) as has been mentioned. If you're looking for the set of all subsets it's the power set that myko and I described. If it's something else, please let us know :P

Answer 7

check question

Answer 8

answer is the power set of all even numbers up to 100:
{{2},{2,4},{2,4,6},{2,4,6,8},...{...,98,100},}
dont forget to include the empty set

Answer 9

and th the set itself

Answer 10

ya, that's right @zzr0ck3r , ty

Answer 11

just notice that {...,98,100} is this set....:)
@zzr0ck3r

Answer 12

One should note that this: {{2},{2,4},{2,4,6},{2,4,6,8},...{...,98,100},} does not properly denote the power set here. That notation leaves out sets like {4,50}, for example. One is best off simply saying "the power set of the set of all even numbers up to 100." You can't actually list them all, because there are 2^50 of them.

Answer 13

but it gives the idea

Answer 14

Yes, but it could give a wrong idea. One might mistakenly think that it was only sets of the form listed, namely, sets starting with two and having some number of even numbers larger than two in increasing order.

Answer 15

ya, you right, i shoud have said that....