Identify the coordinates of the center, the four vertices, and the two foci of this conic section.
I need help finding the 4 vertices and the 2 foci.
Can you identify the major/horizontal axes and their lengths?
major/minor axes*
I don't really understand how to do that
How did you determine this was an ellipse?
Because it is using addition. if it's subtraction, then it is a hyperbole. That's just a trick that someone told me.
Well, a circle uses addition too. How do you know it's not a circle?
Standard form of a circle is (x-h)^2+(y-k)^2=r^2
So what do you notice between the difference of the equation of a circle and the equation of an ellipse
The equation of an ellipse is
There isn't a radius
In the equation of a circle centered at the origin, for example: \[x^2 + y^2 = 2^2\] What happens if you divide both sides by the radius squared?
Then it looks like the equation of an ellipse
So that tells you that a circle is just a special kind of ellipse. A circle is just an ellipse with the same major/minor axes. If you notice the numbers below the 'x^2' and the 'y^2' of the circle I just gave you, you see they are the same numbers. In an ellipse, you notice they are different. That's because they're the major/minor axes, and defines how long the ellipse is stretched out in each direction. If they are stretched out in both directions the same distance, it becomes a circle
oh ok
The largest number under the 'x' or 'y' is the major axis. In your case, the '16' under the 'y' is bigger than the '9' under the 'x' so you know the ellipse is shaped by being elongated along the y-axis and centered at the point you found was the center. The numbers under the 'x' and 'y' are half the lengths of the respective axis squared. So under the 'y' you have a 16, which is 4^2. So the length of the major axis is 8. The vertices of the major axis will be the coordinates at each of the endpoints of the major axis
Okay that makes sense
\[\frac{(x+2)^2}{3^2} + \frac{(y - 3)^2}{4^2} = 1\] If you sketch it, it'll look something like: |dw:1342368693169:dw|
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