Two long uniformely charged thin rods are perpendicular to the x-y plane. At point P, the total electric field E, which is due to both linear charge densities, λ1 (Lamda1) and λ2 (Lamda2) has a magnitude of 288.02 V/m, with components Ex = -65.39 V/m and Ey = 280.50 V/m. The E-field and rods are illustrated in the figure.

Question

anonymous · Answer

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anonymous · Answer

Calculate the magnitude of linear charge density λ2

anonymous · Answer

I know the equation for electric field...not sure how to get linear charge density

anonymous · Answer

I know linear charge density equals charge/volume...not sure how to get there though

anonymous · Answer

Is E = 2kλ/r the right equation?  What is r?

anonymous · Answer

The component Ex=-65.39 V/m can be produced only by Lambda2$$E_{x}=(\lambda_{2}/2 \pi \epsilon_{0}r_{2})\cos(\alpha)$$
And $$ r_{2}=\sqrt{5^{2}+2^{2}}=\sqrt{29}$$
And $$\cos(\alpha)=5/\sqrt{29}$$

I leave the rest for you  :)