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integral of 1/(x^2+x)
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\[\int\limits_{}^{} 1/ (x^2+x) \]
how about factoring first \[\int \frac{1}{x(x+1)}\] i believe you can use partial fractions here yes?
i understand but is it possible to use intyegration by parts as well?
hmm do you mean \[\int \frac 1x \times \frac{1}{x+1}\] interesting...
well i can assure you it's gonna be complicated IF possible
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let u = 1/x du = -1/x^2 dv = 1/x+1 v = ln (x+1) do you see it? the complication i mean
you're gonna have \[\frac{\ln (x+1)}{x} + \int \frac{\ln(x+1)}{x^2}dx\] how do you suppose you can integrate that
okat thank you i see your point
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