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Mathematics 16 Online
OpenStudy (anonymous):

what about -3?-/-3/

OpenStudy (anonymous):

Similarly, make two equations: -3 ? -3 and -3 ? 3 Now find the signs..

OpenStudy (compassionate):

-3 < or > 3? You do the math.

OpenStudy (compassionate):

The first one is \[-3 = -3\]

OpenStudy (anonymous):

You have to find the other now...

OpenStudy (anonymous):

What sign will come in: -3 ? 3

OpenStudy (anonymous):

but all im trying to find is the ? right ... which is =

OpenStudy (compassionate):

Please reword it?

OpenStudy (anonymous):

@rayleigh you're right -3 = -|-3|

OpenStudy (anonymous):

Ramya I think there is something wrong in it...

OpenStudy (anonymous):

please use "|" instead of a slash, so that the question doesnt become confusing :P

OpenStudy (compassionate):

Is -3 < or > 3?

OpenStudy (anonymous):

i dont know how to do that ;P

OpenStudy (anonymous):

why.. negative of absolute value is negative of value itself

OpenStudy (anonymous):

\(-3 = -(3)\) and \(-3 \ne = -(-3)\)

OpenStudy (anonymous):

It will form two equations: \[-3 = -(3)\] and: \[-3 \ne -(-3)\]

OpenStudy (anonymous):

second statement is incorrect. we can use that concept only for inequalities. not here i suppose

OpenStudy (anonymous):

\[|x|\] is always taken as: x and (-x) We first break it and then solve..

OpenStudy (anonymous):

will those 2 equations have different answers? theres only 1 ?

OpenStudy (anonymous):

Yes they will have different answers -3 = -3 and -3 < ..3

OpenStudy (anonymous):

@waterineyes missing the -ve sign outside the mods -3 = -3 and -3 = -3

OpenStudy (anonymous):

negative sign outside the mods sticks. we cannot remove it

OpenStudy (anonymous):

what about this one /p/=2

OpenStudy (anonymous):

p = 2 (or) p = -1

OpenStudy (anonymous):

* p = -2

OpenStudy (anonymous):

thats what i thought

OpenStudy (anonymous):

did i do this right ? /z/=0.3 z=-0.3

OpenStudy (anonymous):

no any |mod| value gives two values. pls check @waterineyes method in the beginning. |z| = 0.3 => z = 0.3 (or) z = -0.3

OpenStudy (anonymous):

i find it useful to think of mods as this : |z| = x+2 means, z value can be 2 units more or 2 units less than x

OpenStudy (anonymous):

youve got what ive got

OpenStudy (anonymous):

hmm

OpenStudy (anonymous):

For the first question. right. its, =

OpenStudy (anonymous):

@ramya I am not removing the sign..

OpenStudy (anonymous):

You said -3 = -|-3|

OpenStudy (anonymous):

im confused |z| = 0.3

OpenStudy (anonymous):

Now this will have two values I show you: |-3| can have two values : -3 and -(-3) Now put these values in the equation: -3 = -(-3) and -3 = -(-(-3)) -3 = +3 (Incorrect) and -3 = -3 (Correct)..

OpenStudy (anonymous):

mod of an EQUALITY can have only one value : +ve

OpenStudy (anonymous):

mod of an INEQUALITY has TWO values : +ve, -ve sorry for the caps... just to highlight :P

OpenStudy (anonymous):

the statement Now this will have two values I show you: |-3| can have two values : -3 and -(-3) is fundamentally incorrect i feel

OpenStudy (anonymous):

I don't think so.. |-x| will always have two values : -x and -(-x)

OpenStudy (anonymous):

thats different. here x is a variable

OpenStudy (anonymous):

still it will have only one CONSTANT value. you can use -x, or +x on the way solving, but you will end up with ONE value

OpenStudy (anonymous):

I have just let it as x.. It can be 3 -3 4 -4 5 7 etc...

OpenStudy (anonymous):

okay.... what about this /z/=0.3

OpenStudy (anonymous):

z = +0.3 z = -0.3

OpenStudy (anonymous):

write a number to represent the situation. then write the opposite of that situation and write a number to represent it. 2 rooms to the right

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