Question

How do I solve using elimination?
x^2+y^2=25
x-y=1

Answer 1

square x= y+1

Answer 2

that's just the answer.

Answer 3

Try to make x^2+y^2=(x-y)^2& also try to make no changes to the question\[(x^2+y^2)=(x^2+y^2-2xy)+2xy\]\[\implies x^2+y^2=(x-y)^2+2xy\]now put the value of x -y in the given equation \[\implies x^2+y^2=(1)+2xy\]

Answer 4

"that's just the answer." ????

Answer 5

oh wait.. I get it.. sorry.

Answer 6

now \[1+2xy=25\]\[2xy=25-1\]\[2xy=24\]\[xy=\frac{24}{2}=12\]\[x={12 \over y}\]

Answer 7

-> x^2 = y^2 +2y+1 and subtract etc...

Answer 8

so now put the value in the equation\[{12 \over y}-y=1\]now solve this & gt ur answer:)

Answer 9

thank you much!