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how do you solve 3+6/t-3=6/t^2-3t?
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Can you make the factor of denominator of Right Hand Side??
I think so
would it be t(t-3) factored?
Yes you are right.. There is one (t-3) on left hand side now can you cancel them??
\[\frac{9}{t-3} = \frac{6}{t(t-3)} \implies \frac{9}{\cancel{(t-3)}} = \frac{6}{t \cancel{(t-3)}}\] Can you find t now??
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how do you solve 3+6/t-3=6/t^2-3t?
Is it?? |dw:1342452918192:dw|
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