Who wants to HELP ME with this one ? Simplify completely: 8x^3+6x^2-4x/-2x

a.−4x^2 − 3x + 2
b.−4x^2 + 3x + 2
c.4x^4 + 3x^3 − 2x^2
d.4x^2 + 6x^2 − 4x

Question

Who wants to HELP ME with this one ? Simplify completely: 8x^3+6x^2-4x/-2x 

a.−4x^2 − 3x + 2
b.−4x^2 + 3x + 2
c.4x^4 + 3x^3 − 2x^2
d.4x^2 + 6x^2 − 4x

richyw · Answer

Did you mean this? this is what you typed...
$8x^3+6x^2-\frac{4x}{-2x}$

anonymous · Answer

yes but all that is over -2x

richyw · Answer

wait like this? $$\frac{8x^2+6x^2-4x}{-2x}$$

anonymous · Answer

yes but its 8x^3 not 8x^2 ..

richyw · Answer

ok yeah I saw that typo. First of all you need to remember your order of operations because what you asked was not that. remember division comes before addition so if you want all of that to be divided by the $-2x$ you need to put brackets around the top part.

richyw · Answer

anyways $$\frac{8x^3+6x^2-4x}{-2x}$$ is the same thing as $$\frac{8x^3}{-2x}+\frac{6x^2}{-2x}-\frac{4x}{-2x}$$ so I hope you can do those three divisions

richyw · Answer

notice how each fraction is just a constant times a power of x? so you can further think about breaking it down like this (this is just the first of three)
$$\frac{8}{-2}*\frac{x^3}{x}$$
now the first one should be simple, for the second just remember that for exponents with the same base you add the exponents if you multiply them and subtract the exponents if you divide. so this becomes $$-4*x^{3-1}=-4x^2$$

anonymous · Answer

ok. so i did 8x^2=64 + 6x^2=36 + 4x am i doing it right ?

richyw · Answer

just do that for the other two. I have to go to my class now but make sure you do that. The answer you should get is A.

richyw · Answer

no you didn't do it right

anonymous · Answer

okay ill try, thanks for helping me ! :)

richyw · Answer

you have squared 8, but you aren't squaring 8 you are squaring the variable and multipliying that by 8. and no worries!