Question

How do you solve this problem? 5x-4=square root 5x-4?

Answer 1

By eye ball, x=1 will work if\[5x-4=\sqrt{5x-4} \]

Answer 2

Please I need to see the step to learn.

Answer 3

Square and expand each side.\[(5x-4)^2=\left(\sqrt{5x-4}\right)^2 \]\[25 x^2-40 x+16=5 x-4 \]Move the RHS to the LHS and simplify.\[16-40 x+25 x^2-(-4+5 x)=0\]\[25 x^2-45 x+20=0 \]The LHS factors as follows:\[5 (x-1) (5 x-4)=0 \]Can you complete the solution from here?

Answer 4

next step please?

Answer 5

x=5 and x=-4

Answer 6

(x-1) = 0
x = 1

(5x-4) = 0
x = 4/5

Answer 7

Thank you.

Answer 8

You're welcome.