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Mathematics 15 Online
OpenStudy (anonymous):

A ladder leaning against a wall makes a 60 degrees angle with the ground. The base of the ladder is 4 m from the building. How high above the ground is the top of the ladder?

OpenStudy (anonymous):

tangent = opposite/adjacent and tangent*adjacent (base of ladder from the building) = opposite (height of ladder above ground) So: tangent 60 degrees*3 = 5.196152423 Therefore: Top of the ladder above ground = 5.2 meters correct to one decimal place.

OpenStudy (anonymous):

multiply by 3 or 4? @AlexPR787

OpenStudy (anonymous):

The right triangle formed by the wall, ground and ladder has sides in the ratio of 1::2::sq-rt-of-3. The shortest side is the one opposite the 30 degree angle, i.e., the given distance from wall to base of the ladder--3 m.

OpenStudy (anonymous):

The length of the ladder represents the hypotenuse of the triangle, and is twice as long, hence 6 m. :

OpenStudy (anonymous):

And the height of the ladder's top from the ground is proportional to the third side whose length is sq-rt-3 times that of the shortest side. Sq-rt-3 is about 1.732, so height of the ladder's top at the wall is about 5.20 m, or 520 cm. hope it helps.

OpenStudy (anonymous):

can you draw it for me plz?

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