Question

the area rectangle portion of a national park is (48x^2+16x) square km.if the lenght is 8x km long,what is the width,in km?
please help me

Answer 1

It's like the last one we did. Divide EACH term of the AREA by the length.

Answer 2

\[48x ^{2}/8x \]
and
\[16x/8x\]

Answer 3

Then add your two results together (you won't be able to "combine" them because they aren't LIKE TERMS. But you can put them side by side.)

Answer 4

What'd you get?

Answer 5

its hard and my first time doing it

Answer 6

Maybe stating it a different way will help. You know that:
Area = Width * Length
\[Area = 48x^2 + 16x\]
Length = 8x
Width = ?

So you have \[48x^2+16x = 8x\space \times \space ?\] Solve for your ?
First thing you would do is to divide both sides by 8x
\[\frac{48x^2 + 16x}{8x} = \frac{8x \times ?}{8x}\] Leaving you with
\[\frac{48x^2 + 16x}{8x} = ?\] Break it into separate fractions
\[\frac{48x^2}{8x} + \frac{16x}{8x} = ?\]
Solve and your answer will be the width you are looking for.

Answer 7

Did you get it?

Answer 8

6x + 3