the area rectangle portion of a national park is (48x^2+16x) square km.if the lenght is 8x km long,what is the width,in km? please help me
It's like the last one we did. Divide EACH term of the AREA by the length.
\[48x ^{2}/8x \] and \[16x/8x\]
Then add your two results together (you won't be able to "combine" them because they aren't LIKE TERMS. But you can put them side by side.)
What'd you get?
its hard and my first time doing it
Maybe stating it a different way will help. You know that: Area = Width * Length \[Area = 48x^2 + 16x\] Length = 8x Width = ? So you have \[48x^2+16x = 8x\space \times \space ?\] Solve for your ? First thing you would do is to divide both sides by 8x \[\frac{48x^2 + 16x}{8x} = \frac{8x \times ?}{8x}\] Leaving you with \[\frac{48x^2 + 16x}{8x} = ?\] Break it into separate fractions \[\frac{48x^2}{8x} + \frac{16x}{8x} = ?\] Solve and your answer will be the width you are looking for.
Did you get it?
6x + 3
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