Question

Solve the exponential equation. Express the solution in terms of logarithms.

7^(4x+2)=6^(x-2)

Answer 1

\[\ln (7^(4x+2))=\ln (6^(x-2))\]
so \[(4x+2)*\ln(7)=(x-2)\ln(6)\]
can you finish it by yourself ?!

Answer 2

no im a little confused

Answer 3

wait, do you put all x's on the left?

Answer 4

yeaaaah ! you have a problem with that ?! :)

Answer 5

do you have to divide by x-2 on both sides?

Answer 6

?

Answer 7

ln(a^b)=bln(a)
and consider that ln(7) and ln(6) two real numbers...you can solve equations like : "4x+6=-3x+2" put x's on the left and you will get the answer !

Answer 8

which part you didn't understand ?! :)

Answer 9

I didnt understand how to get the final answer ;)