Question

Integral help
y=cosx, y=2-cosx, 0 13 years ago

Answer 1

There are two y's.

you need integral of what??

Answer 2

I'm trying to find the area in-between the 2 curves

Answer 3

in that interval of 0 to 2pi

Answer 4

Sorry I have no clue..

Answer 5

haha ok

Answer 6

Can you show me your steps??
May be I can help you somewhat..

Answer 7

\[2-\cos(x)\geq \cos(x)\] so your area between the curves is found via
\[\int_0^{2\pi}2-\cos(x)-\cos(x)dx=\int_0^{2\pi}2-2\cos(x)\]

Answer 8

should be straightforward to compute, it is
\[\int_0^{2\pi}2dx-2\int_0^{2\pi}\cos(x)dx\] first part is \(2\pi\times 2=4\pi\) from your eyeballs, second one is what you get when you take the anti derivative of sine, and evaluate

Answer 9

satellite73 is correct.

Answer 10

By the way @satellite73, I usually use my brain and a pencil to evaluate things. Not necessarily eyeballs

Answer 11

sure but not \(\int_a^b cdx=c(b-a)\)