Solve for x: 2^(x+4) = 4^(x-2)

A. 0
B. 1
C. 4
D. 6
E. 8

Question

Solve for x: 2^(x+4) = 4^(x-2)

A.	0
B.	1
C.	4
D.	6 
E.	8

anonymous · Answer

wait r u suppose deal with jux the exponents 1st?

anonymous · Answer

$$2^{(x+4)} = 4^{(x-2) }$$$$2^{(x+4)} = (2^2)^{(x-2) }$$$$2^{(x+4)} = (2)^{2(x-2) }$$$$2^{(x+4)} = 2^{(2x-4) }$$

anonymous · Answer

When we are left with this we note that in order for both sides to be equal the exponents have to be equal

anonymous · Answer

go with @Romero

anonymous · Answer

you are then left with trying to solve tthis equation for x
$$x+4=2x-4$$

anonymous · Answer

As hard tricky as this question is all you really have to do is solve that last equation I posted for x

anonymous · Answer

The reason we set them equal is because the exponents to be equal. That will make the statement true

anonymous · Answer

oh so all u need to do for such questions is to find a common sort of coefficient?

anonymous · Answer

so in this the answer is 8 right?

anonymous · Answer

how did you get 8?

anonymous · Answer

Actually yeah you are right. I got confused.

anonymous · Answer

Good job!

anonymous · Answer

x+4=2x-4
4=x-4
x=8

anonymous · Answer

oh ok thanx