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is it possible integrate (sinx/x) from 0 to infinity without using engineering math????
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\[\int\limits_{0}^{\infty} \frac{\sin x}{x} dx\] ?
yes
are u familiar with laplace transform?
yes !!
\[\int\limits_{0}^{\infty} \frac{\sin x}{x} dx= \int\limits_{0}^{\infty} \int\limits_{0}^{\infty} e^{-xy} dy \sin x \ dx=\int\limits_{0}^{\infty} \int\limits_{0}^{\infty} e^{-xy} \sin x \ dy dx=\int\limits_{0}^{\infty} \int\limits_{0}^{\infty} e^{-xy} \sin x \ dx dy\] intervals are equal so dx dy=dy dx now u have (using laplace transform) \[\int\limits_{0}^{\infty} \int\limits_{0}^{\infty} e^{-xy} \sin x \ dx dy=\int\limits_{0}^{\infty} \frac{1}{1+y^2} dy=tan^{-1} \infty=\frac{\pi}{2} \]
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oh very well thank u
welcome
@mukushla
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