help please...Choose the slope-intercept equation of the line that passes through the point (6, 4) and is parallel to y = 1/3x - 3.
how do you do this?
HInt: Paralell lines have same slopes.
You will identify the slope of the given equation first.
hint: y=mx+b where m is the slope
Note that y =1/3x - 3 is in the form y = mx+b, where m = slope.
So, the slope of the given equation, will be the same on the slope of the equation we will solve.
slope is 1/3
After that, you will have the slope and the point, you may use the Point-Slope Form: y -y1 = (slope)(x-x1)
that is right, slope is 1/3!
so, plug-in 4 for y1, 6 for x1, and 1/3 for the slope.then simplify.
example: if we have (1,2) and slope = 2/3, then: y - 2 = (2/3)(x-1).
then, y-2 = 2/3x - 2/3
isolating y on left side: y = 2/3x + 4/3
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