Your piggy bank has a total of 47 coins in it; some are dimes and some are nickels. If you have a total of $3.95, how many nickels do you have?
Help Please.. :)
set up 2 equations in 2 unknowns the number of dimes and nickels = 47: a + b = 47 some set of "a" dimes and "b" nickels = 3.95: a(.10) + b(.05) = 3.95
systems of equations can be solved by substitution, or elimination
a + b = 47 a(.10) + b(.05) = 3.95 pick your poison :)
since we want to get the number of nickels (b) id opt to get rid of the "a" parts
im confused lol
Given: d = qty of dimes Given: n = qty of nickels Given: d + n = total coins =47 Given: total $ = 3.95 Write equations: d + n = 47 10d + 5n = $3.95 d = 47 - n substitute: 10(47 - n) + 5n = 395 470 - 10n + 5n = 395 5n = 75 n = 15 ea d = 47 - 15 = 32 ea CHECK: (10)(32) + (5)(15) = 395/100 = $3.95
is this better ?
yes thank you :)
yur welcome =)
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