What is the sum of a 12–term arithmetic sequence where the last term is 13 and the common difference is –10?
There is something wrong @Mimi_x3 ..
I think so too lol I haven't done these in a while..
\[ T_n = a +(n-1)d\] \[ T_{12} = a + (12-1)*-10 = 13\] \[ a-120 +10 = 13\] \[ a -110 = 12\] a = 122
\[13 = a + (12-1) (-10) \implies 13 = a -110 \implies a = 123\]
What are we doing we don't know @Mimi_x3 Ha hah a..
Another typo lol \(a = 123\)
Sorry brain dead at 2 am. a -110 = 13 => a =123
So, \(a = 123\) Now find the sum.. \[\huge Sum = \frac{n}{2}(a + l)\] n = 12. a = 123 and l = 13 Calculate the sum now.. @emkaye16
What happens?? Another brain dead?? @Mimi_x3
My internet speed is just as same as that of an ant..
nothing lol i thought there was another mistake; but there wasnt lol
my brain speed is so slow today :(
@Mimi_x3 I think here we are talking there is no one other watching us.. Ha haha..
lol even the asker is not responding; probably got scared from our mistakes :P
so the answer is 816?
Yes you are right @emkaye16 Sorry I was busy somewhere else.. \[\huge \color{blue}{\textbf{Keep It Up...}} \color{green} {\checkmark}\]
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