The wing color of a certain species of moth is controlled by alleles at a single locus. Gray (G) is dominant to white (g). A scientist studied a large population of these moths, tracking the frequency of the G allele over time, as shown in the figure below: Assuming that the population was in Hardy-Weinberg equilibrium for this gene, what percentage of the moth population was heterozygous in 1960?
A) 20% B) 32% C) 40% D) 64%
Hmm.. In 1960 f(G) = p = 0.8, as p+q = 1, q = 0.2, \( f(gg) = q^2\) = 0.04 = 4%... Its 4 not 40 !! @vera_ewing
But 4 is not an answer choice! Which one should I choose?
Assuming that the population was in Hardy-Weinberg equilibrium for this gene, what percentage of the moth population was heterozygous in 1960?
convert 0.04 into %
It's 4%, but that is not an answer choice. Did you calculate it correctly??
hmm, i rechecked the question from google ref which says... The wing color of a certain species of moth is controlled by an allele at a certain locus. gray (G) is dominant to white (g). A scientist studied a large population of these moths, tracking the frequency of the G allele over time, as shown in the figure. Assuming that the population was in Hardy Weinberg equilibrium for this gene, what percentage of the moth population was homozygous recessive (gg) in 1960? Is it 4%, 32%, 50% or 64%? Figure: http://tinypic.com/r/34pgear/6 then, its a mistake in the question paper..!
Koik, that is a different question!
@vera_ewing yup, it's right... its 4 not 40 !
That's a different question, koik. The answer choices are not the same.
lol, i will try again, sorry just a min..
ok
i'm sorry, again i got same result... @dan815
@dan815
ive seen this question before ... (p+q)^2 = pp + 2pq + gg were p and q are alleles? and pp, gg, pg are combinations, genotypes maybe?
and p+q=1
I think so, yes ok
2(.8)(.2) seems to fit for 1960
hetero is the pq parts
Ok so then what?
so then 2(.8)(.2) should be the solution
using G and g (G+g)^2 = GG + 2Gg + gg, and G+g = 1 in 1960, G = .8, so g=.2 hetero is the Gg term
Ohh ok thanks so much.
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