Question

Post the whole process to solve this please :D
\[\large \int_{-1}^{0} \frac{1}{2}x+\frac{1}{2}dx\]

Thanks!

Answer 1

\[\int\limits \frac{1}{2}xdx+\frac{1}{2} \int\limits dx\]
\[(\frac{1}{4}x^2+\frac{1}{2}x)|^0_{-1}\]
\[[(\frac{0^2}{4}+\frac{0}{2})-(-\frac{1}{2})]=\frac{1}{2}\]

Answer 2

I got \(\large \frac{1}{4}\) using geometry.. :|

Answer 3

That's because I left out part of the last integral reult in the last line, ha

\[[(\frac{0^2}{4}+\frac{0}{2})-(-\frac{1}{4}(-1)^2-\frac{1}{2})]=\frac{1}{4}\]