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Can you apply product rule to : \[\Large f(x)=e^{x}.sin(x)\]
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\[\frac{dy}{dx} = e^x \cdot \sin(x) = e^x \cdot \sin(x) + e^x \cdot \cos(x) = e^x(\sin(x)\cos(x))\]
\[f^{(1)}(x)=e^{x}.sin(x)+e^{x}.cos(x)\] hmm also it looks same and how we done it according to \[f^{'}(x)=u^{'}v+uv^{'}\] i could not understand it
Derivative of e^x is e^x, so in both terms, it's going to be the same
is it a rule ?
Derivative of e^x = e^x is a rule, yes
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ok thank you very much eyeh8maf
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