Question

Write an equation for a circle with center at (2,3) and radius of 6

Answer 1

(x-2)^2+(y-3)^2=36

Answer 2

Equation of circle is given by:

\[(x-h)^2 + (y-k)^2 = r^2\]

Where, (h,k) = center and r = radius..

Answer 3

thnks u guys

Answer 4

So according to this:

\[(x-2)^2 + (y-3)^2 = 6^2\]

\[(x-2)^2 + (y-3)^2 = 36\]

Answer 5

Welcome dear..

Answer 6

thnk u i had to use an example so i wud kno how to do the rest so thnks

Answer 7

Write an equation for a circle with center at (-2,7) and diameter of 14.
i got (x-2)^2+(y-7)^2=196
but they said it was wrong
@waterineyes

Answer 8

@waterineyes ?

Answer 9

You are given with diameter..

firstly find the radius from it:

2*r = diameter

2*r = 14

r = 7

S0, on RHS 49 will come..

Answer 10

im lost so it ='s 49 not 196?

Answer 11

Yes you have to calculate radius first..

Answer 12

but i thought tht 14 wud be ^2?

Answer 13

No that is the diameter..

You have to half it when diameter is given..

Answer 14

but u didnt half 6

Answer 15

on the other problem

Answer 16

ohhhhhhh nevermind 6 was the radius

Answer 17

nd 14 is the diameter

Answer 18

yes..

Answer 19

lol im sorry i get it

Answer 20

it still says im wrong even with the 49???