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I'm trying to use integrals to find the arc length of y=2x-5 in the interval [-1,3]
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you are wanting to integrate along the arc, ir integrate with respect to "ds" .
yes with respect to dx. I'm trying to use the arc length formula L= integral of (sqrt(1+(dy/dx)^2)dx)
|dw:1342649289785:dw| because these are differentials, ds becomes: \[\sqrt(dx^2 + dy^2)\]
oh, ok
you already know the formula
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good
yes, Im just having a hell of a time using it lol
so first take the derivative of the equation
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