Question

(x^2 - 1)/(9x)/(x^2 + 2x + 1)/(3x^2)

Answer 1

simplify?

Answer 2

\[\frac{\frac{x^2-1}{9x}}{\frac{x^2+2x+1}{3x^2}}\]?

Answer 3

yes.

Answer 4

alright so do you know that

\[\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a}{b}*\frac{d}{c}?\]

Answer 5

basically multiplyng by one in the form of the reciprocal to get one on the bottom

Answer 6

yes, i simplified it to that.

Answer 7

but the answer i got wasn't in the choices, so i wanted to know what i did wrong

Answer 8

\[\frac{x^2-1}{9x}*\frac{3x^2}{x^2+2x+1}\]

Answer 9

did you factor \[x^2-1,3x^2,x^2+2x+1\]

Answer 10

ohhh. I tried making them have the same denominators first

Answer 11

before i factored

Answer 12

no need to make the same denominator, you're multiplying

Answer 13

oh haha i forgot about that

Answer 14

alright im gonna try doing this again

Answer 15

alright i'm going to go eat and 'll check the answer when i get back

Answer 16

k i got x(x-1)/3(x + 1)

Answer 17

right