Question

find the limit

Answer 1

0? xD

Answer 2

@rebeccaskell94 why'd you tell the correct answer o.O

Answer 3

;D Because I am boss

Answer 4

\[\lim_{x \rightarrow 7}\ln(5-3x)\]

Answer 5

Well, that isn't 0...

Answer 6

darn ln :/

Answer 7

then do yall have the answer...
@lgbasallote @rebeccaskell94

Answer 8

im trying to remember how to do it...

Answer 9

Well, I could be creative with an answer. But, in all honesty, I have no clue.

I mean...yeah. If you want to pass I am not the person to ask lol

Answer 10

@waterineyes do you remember limits?

Answer 11

The above is the question??

Answer 12

I think we can we use L Hospital rule here..

Answer 13

\[\lim_{x \rightarrow 7} \left(\ln (5 - 3x) \right)\]

Answer 14

but it's not in the form 0/0

Answer 15

\[\lim_{x\to 7}\ln (5-3x)\]
put x=7
\[\ln(5-21)=\ln (-16)\]
log can't have a negative quantity inside, so limit doesn't exist

Answer 16

or \(\infty/\infty\)

Answer 17

Really @ash2326 ??

Answer 18

Yes, limit doesn't exist

Answer 19

that's what i thought too..but there must be some simplification process to give a value to x

Answer 20

i mean the limit

Answer 21

thanks