Question

how to find nth derivative of sin x

Answer 1

Start taking derivatives... then look for a pattern.

Answer 2

\[y = \sin x\]
\[y' = \cos x\]
\[y'' = -\sin x\]
\[y''' = -\cos x\]
\[y'''' = \sin x\]
then the process repeats do you agree?

Answer 3

You will see it after about 4 or 5 derivatives... then guess...

Answer 4

yup i agree
bt thn hw to proove it by mathematical induction?

Answer 5

Ok, you first have to show the base case. That is n = 0. Then you have to assume it is true for the nth case, then show that the formula holds for the n+1st case. But you need a formula first or a statement that you think is true.

Answer 6

ok...

Answer 7

So how do you want to represent the derivative pattern in terms of n...

Answer 8

yea...

Answer 9

ok ok......... got it....... thanx :)

Answer 10

what did you get for the expression involving n?

Answer 11

m doing it.......:) will tell d ans once i cmplete k?

Answer 12

Sounds good.