Question

https://secure.aleks.com/alekscgi/x/math2htgif.exe/NM?%2E%23%3Fal%7B%3D%3A%3Flufq%3D1%3F%2Cal%7B%3D%23%3E%23%3Fal%7B%3D7%3Flufq%3D0%3F%2Cal%7B%3D%23z%23%2E%23%3Fal%7B%3D6%3Flufq%3D7%3F%2Cal%7B%3D

Answer 1

Start by adding 4/5ths to both sides of the equation. Then resolve the fraction on the left hand side of the equation by using either the lowest common factor, or by cross multipltication, then multiply by 3 and divide by 4.

Answer 2

say what now? im confused

Answer 3

\[\frac{-9}{2}=\frac{4y}{3}-\frac{5}{4}\]
\[\frac{5}{4}-\frac{9}{2}=\frac{4y}{3}\]

Do you know to cross multiply?

Answer 4

yes
just 5x2 and 9x4?

Answer 5

(5x2 -9x4)/2*4

Answer 6

oh ok soo now what?

Answer 7

cross multiply again

Answer 8

\[\frac{-9}{2}=\frac{4y}{3}-\frac{5}{4}\]
\[\frac{5}{4}-\frac{9}{2}=\frac{4y}{3}\]
\[\frac{5*2-9*4}{4*2}=\frac{4y}{3}\]
\[\frac{10-36}{8}=\frac{4y}{3}\]
\[\frac{-13}{4}=\frac{4y}{3}\]
\[\frac{3*-13}{4*4}=y\]
\[\frac{-39}{16}=y\]

I hope this is right.

Answer 9

ok this makes more sense and im about to test it out

Answer 10

great! thanks for your help! wanna help me with a few others?

Answer 11

guess not. thanks again!